$\frac{(2x+1)(3x-2)}{24x^{2}-4x-8} = \frac{(2x+1)(3x+2)}{4(6x^{2}-x-2)} = \frac{(2x+1)(3x+2)}{4(6x^{2}-4x+3x-2)} = \frac{(2x+1)(3x+2)}{4[2x(3x-2)+(3x-2)]} = \\ \\ = \frac{(2x+1)(3x+2)}{4(2x+1)(3x-2)} = \frac{3x+2}{4(3x-2)} = \frac{3x+2}{12x-8}$

8 0

2 years ago

steve started with$250 and spent $25 per week. Use x for time and y for savings.write an equation to represent the situation and

MariettaO [177]

Answer:

y = 250-25x

Step-by-step explanation:

5 0

2 years ago

Write an equation in slope-intercept form for the line with slope -4 and y-intercept -1.​

Write an equation in slope-intercept form for the line with slope -4 and y-intercept -1.