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lara [203]
3 years ago
12

What is the slope for (4,7) and (-1,4)?​

Mathematics
1 answer:
harina [27]3 years ago
7 0

<em>The slope is 7/4</em>

<em>This means that for every 7 that Y changes, X changes by 4. Also, the problem would not go through the origin of a graph.</em>

<em>Hope this helps and have a nice day.</em>

<em>-R3TR0 Z3R0 (復古零) </em>

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jeka57 [31]

Solution:

we are given that

A student has some​ $1 and​ $5 bills in his wallet.

Let there x $1 bills and y number of $5 bills.

He has a total of 14 bills that are worth ​$34.

So we can write

x+y=14

x+5y=34

Now solve these two equations together using substitution as follows

14-y+5y=34\\&#10;\\&#10;4y=34-14\\&#10;\\&#10;4y=20\\&#10;\\&#10;y=5\\&#10;\\&#10;x=14-y=14-5=9\\

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3 years ago
How many solutions will there be to the following equation?16x^2=100
djverab [1.8K]

Answer:

2 solutions; x=2.5     x=-25

Step-by-step explanation:

16x^2 = 100

x^2 = 100/16

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4 0
3 years ago
YOOO MARKIN BRAINIEST !!
Brilliant_brown [7]
Y ≥ 2x-5
y-intercept is -5, from there go 2 up 1 over ( slope is rise over run)
greater than or equal so the line is connected
now find the shaded area by plugging in (0,0)
0 ≥2(0)-5
0 ≥-5 is correct so shade the area that to the left of the line, (the whole area that including (0,0))

y<-3x
y intercept is 0 so start from there and go down 3 right 1 (or go up 3 left 1)
broken like cause no or equal sign
the (0,0) is on the line so use (1,1) to find the answer
1<-3(1) is incorrect so shade the area that dies not include (1,1) or the entire area to the left of that line

you can see the section where both shaded area cross, thats the answer so erase every area you shaded that isn’t the answer so
THE ANSWER IS C
3 0
4 years ago
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Without computing, decide whether the value of each expression is much smaller than one, closer to one, or much greater than one
d1i1m1o1n [39]

Answer:

C: closer to one

D: much smaller than one

E: much greater than one

F: much smaller than one

Step-by-step explanation:

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2 years ago
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Vehicle B need fewer repairs on average, but the number of repairs per vehicle has greater variation
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