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MA_775_DIABLO [31]
3 years ago
14

A survey showed that 35% of the students prefer plain white milk over chocolate milk. If the school has 1200 students. How many

students prefer chocolate milk?
Mathematics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

The number of students who prefer chocolate milk is 780 .

Step-by-step explanation:

Given as :

The total number of students in the school = 1200

The percentage of students who prefer plain white milk = 35 %

Let the number of students who prefer chocolate milk = x

Now, ∵ The percentage of students who prefer plain white milk = 35 %

∴ The percentage of students who prefer chocolate milk = 100 % - 35 % = 65%

So , As The number of  students who prefer chocolate milk = x

Or, 65 % of total number of students in school = x

So, x = \frac{65}{100} × 1200

or, x = \frac{65\times 1200 }{100}

∴  x = 780

So, the number of students who prefer chocolate milk = x = 780

And  students who prefer plain white milk = 1200 - x = 1200 - 780 = 420

Hence, The number of students who prefer chocolate milk is 780 . Answer

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Step-by-step explanation:

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Step-by-step explanation:

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The endpoints of are A(2, 3) and B(8, 1). The perpendicular bisector of is , and point C lies on . The length of is units. The c
Blababa [14]

Answer:

The Coordinates of Point C are C(5,2)

The slope of CD is 3  

The possible coordinates of point D(a,b) are (6, 5) and (4, -1)  

Step-by-step explanation:

According to the Question,

  • Given, The end points of AB are A(2,3) and B(8,1). The perpendicular Bisector of AB is CD, and point C lies on AB. The length of the CD is √10 units.

Now, Let The Coordinates of Point C are C( x , y ) .  

  • Thus, C( x , y ) = ((8 +2) / 2 , ( 1 + 3 )/ 2 ) ⇒ (10/2 , 4/2) ⇒ (5 , 2)

The Coordinates of Point C are C( x , y ) ⇒C(5, 2).  

And, The slope of AB = (1 - 3)/(8 - 2) ⇒ -2/6 ⇔ -1/3 .

  •       Thus, The slope of CD is  -1/(The slope of AB) =  -1/(-1/3) ⇔  3.

Let the coordinate of D be (a, b) then

⇒ √{ (b - 2)² +(a - 5)² } = √10

 on squaring both sides we get,

 ⇒ a² - 10a + 25 + b² - 4b + 4 = 10

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We Know, the slope of CD = 3

⇒Thus,  (b - 2)/(a - 5) = 3

⇒ b - 2 = 3a - 15

⇒ b = 3a - 13 ⇔⇔ (Equation 2)

Putting value of Equation 2 into Equation 1, We get

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⇒a² + 9a² - 78a + 169 - 10a - 12a + 52 = - 19

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Therefore, the possible coordinates of point D(a,b) are (6, 5) and (4, -1).

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