3x^2+11x-4=10x-1
3x^2+11x-10x-4+1=0
3x^2+x-3=0
Δ=1^1-4*3*(-3)=1+36=37
x1=(-1+V37)/6
x2=( -1-V37)/6
Answer:
Step-by-step explanation:
Answer:
Well your using absolute value and everything in absolute value is positive so you get rid of the negative.
Step-by-step explanation:
So you distribute the negative into the absolute value equation . And it leaves you with
|-1+5a|=29 now you can solve
your subtract your -1 from both sides bc you are solving for a
that gives you
5a=30 then you divide 5 divided by 30 is what 6 so that’s your answer
a=6
3x + 4y = 31
2x - 4y = -6
*The +4 and -4 in the center of the equation cancel out because 4-4 = 0*
3x = 31
2x = -6
------------
*add like terms*
3x + 2x = 5x
31 - 6 = 25
So now you should have this written on your paper ... > 5x = 25
*Divide by 5 on each side*
5x = 25
_ _
5 5
x = 5
Answer:
Step-by-step explanation:
center is (-2,3)
