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Luden [163]
3 years ago
9

Kenji's electricity bill costs $21.56 per month plus $2.46 per kilowatt hour. How many kilowatt hours can he use and keep his bi

ll to no more than $54?
Mathematics
1 answer:
Alik [6]3 years ago
5 0

Answer:

Kenjii can use 13.19 kilowatt-hour.

Step-by-step explanation:

Giving the following information:

Kenji's electricity bill costs $21.56 per month plus $2.46 per kilowatt-hour.

<u>First, we will structure the total cost formula:</u>

Total cost= 21.56 + 2.46*x

x= kilowatt-hour

54= 21.56 + 2.46x

32.44= 2.46x

13.19= x

Kenjii can use 13.19 kilowatt-hour.

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Which of the following could be the graph of y = –xn where n is odd?
mina [271]

Answer:

Step-by-step explanation:

I think you meant y = -x^n, where ^ denotes exponentiation.

If n is odd, the graph begins in Quadrant II and decreases through the origin into Quadrant IV.  This is true of -x, -x^3, -x^5, and so on.

8 0
3 years ago
Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t
frozen [14]

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

 c^{2} =a^{2}+b^{2}+2abcos\alpha---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and \alpha is the angle between a and b .

In equation 1 , the maximum and minimum values of cos\alpha are 1 and -1.

 so the value of c  lies in between

⇒ \sqrt{a^{2}+b^{2}-2ab   } and  \sqrt{a^{2}+b^{2}+2ab  }   = |a-b| and |a+b|

Given a=13.2 and b=6.7 so the the side lies in between  |13.2-6.7| and |13.2+6.7|

  so the third side lies between 6.5 and 19.9

3 0
3 years ago
Is 3/20 larger then 2
aleksley [76]
To find out is 3/20 is larger than 2 we will convert 3/20 to a decimal. Lets do it:- 

3/20
3 ÷ 20 = 0.15

Is 0.15 larger than 2?

No, 0.15 is not larger than 2.

So, 3/20 isn't larger than 2.

Hope I helped ya!! xD
8 0
3 years ago
Read 2 more answers
A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is
Otrada [13]

Answer:

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 29.5

Standard deviation r = 5.2

Number of samples n = 59

Confidence interval = 90%

z-value (at 90% confidence) = 1.645

Substituting the values we have;

29.5+/-1.645(5.2/√59)

29.5+/-1.645(0.676982337100)

29.5+/-1.113635944529

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

7 0
2 years ago
What is the solution of √1-3x=x+3
grandymaker [24]

Answer:

x = -1

Step-by-step explanation:

8 0
2 years ago
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