All categories

3 years ago

What games do you play ?

Mathematics

2 answers:

kherson [118]3 years ago

8 0

Mario Cart
What about you?

algol133 years ago

8 0

Answer:

I play "eat and run"

Step-by-step explanation:

Here's how to play: You go to your fridge without stepping on a LEGO, then you pen the door without waking anyone. Next you grab all the food, and hurry back before your demon little sister catches you :D

You might be interested in

Simplify 3x*3y^2/9xy^5 and explain please

vivado [14]

The answer is 1/y^3

7 0

3 years ago

Solve w=x+yz for y.<br><br><br><br> Solve the equation above for z.

Natali [406]

The answer is w-x/y=z

8 0

3 years ago

Read 2 more answers

Expand the linear expression 4(10x-4 )

Cloud [144]

Answer:

40x- 16

Step-by-step explanation:

Because 4 times 10x is 40x and 4 times 4 is 16 so the answer is 40x-16

6 0

3 years ago

Read 2 more answers

Which questions can be answered by finding the volume? Check all that apply. How much wrapping paper is needed to cover a box? H

EleoNora [17]

How much juice is inside the juice box? How much sand is needed to fill a sandbox?
How much ice can fill a cooler?

(Volume is a measure of the inside contents or the space inside)

8 0

3 years ago

Read 2 more answers

All steps for: x/x-2 + x-1/x+1= -1

lorasvet [3.4K]

Answer:

$\large\boxed{x=0\ \vee\ x=1}$

Step-by-step explanation:

$Domain:\\\\x-2\neq0\ \wedge\ x+1\neq0\\\\x\neq2\ \wedge\ x\neq-1\\\\\boxed{D:\ x\in\mathbb{R}-\{-1,\ 2\}}\\\\=============================$

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1\qquad\text{subtract}\ \dfrac{x-1}{x+1}\ \text{from both sides}\\\\\dfrac{x}{x-2}=-1-\dfrac{x-1}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-(x+1)}{x+1}+\dfrac{-(x-1)}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-(x+1)-(x-1)}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-x-1-x+1}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-2x}{x+1}\qquad\text{cross multiply}$

$x(x+1)=-2x(x-2)\qquad\text{use the distributive property}\\\\(x)(x)+(x)(1)=(-2x)(x)+(-2x)(-2)\\\\x^2+x=-2x^2+4x\qquad\text{add}\ 2x^2\ \text{to both sides}\\\\3x^2+x=4x\qquad\text{subtract 4x from both sides}\\\\3x^2-3x=0\qquad\text{distributive}\\\\3x(x-1)=0\iff 3x=0\ \vee\ x-1=0\\\\x=0\in D\ \vee\ x=1\in D$

4 0

3 years ago

Read 2 more answers