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Murljashka [212]
3 years ago
14

Sarah has a floor plan of the Jefferson building. The actual building is 168 feet long. What is the scale factor for the floor p

lan?
A) 1 in : 6 feet
B) 1 in : 28 feet

C) 1 in : 68 feet
D) 1 in : 96 feet
Mathematics
2 answers:
Bas_tet [7]3 years ago
4 0
The answer is B. Hope I helped!
olganol [36]3 years ago
4 0

Answer:

B

Step-by-step explanation:

B

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DeShawn pays 8$ for 12 pounds of sugar. What is the price per pound of sugar
Serhud [2]

Answer:

DeShawn pays .67 cent per pound of sugar

3 0
3 years ago
A survey found that women's heights are normally distributed with mean 62.8 inches and standard deviation of 2.5 inches. This su
Jet001 [13]
<span>a) 

Z*_Upper = (76 - 62.7)/2.5 = 5.32

Z*_Lower = (57 - 62.7)/2.5 = -2.28 

The requirement is to get p(-2.28 < Z < 5.32) = p(Z<5.32) - p(Z<-2.28). 

Use normal distribution table to get the answer for p and multiply with 100 to get the percentage. 

The other questions are now easy for you to answer on your own. Hope it helps.

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4 0
3 years ago
Read 2 more answers
A cone is placed inside a cylinder as shown. The radius of the cone is half the radius of the cylinder. The height of the cone i
Dovator [93]

we can use

volume of cone formula

V=\frac{1}{3} \pi r'^2 h'

where

r' is radius of cone

h' is height of cone

we are given

The radius of the cone is half the radius of the cylinder

so,

r'=\frac{r}{2}

The height of the cone is equal to the radius of the cylinder

so,

h'=r

now, we can plug values into formula

we get

V=\frac{1}{3} \pi (\frac{r}{2})^2*r

we can simplify it

V=\frac{1}{12} \pi r^3

so, option-C.........Answer

7 0
3 years ago
Which expression is equivalent to 6x^5z^3/4x^4z^2?
Reika [66]
<span>4x^2y + 12xy^2 + 9y^3</span>
8 0
4 years ago
Read 2 more answers
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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