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4 years ago

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Suppose that a random sample of 200200 twenty-year-old men is selected from a population and that these men's height and weigh

t are recorded. a regression of weight on height yields modifyingabove weight with caret equals left parenthesis negative 102.3923 right parenthesis plus 4.0582 times height comma upper r squared equals 0.83 comma ser equals 10.5weight=(−102.3923)+4.0582×height, r2=0.83, ser=10.5, where weight is measured in pounds and height is measured in inches. what is the regression's weight prediction for someone who is 7373 inches tall? the regression's weight prediction for someone who is 7373 inches tall is nothing pounds. (round your response to two decimal places.)

1 answer:

Bezzdna [24]4 years ago

7 0

The prediction is 193.86 lb.

Substituting 73 for x, we have:

-102.3923 + 4.0582*73 = 193.86

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Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

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Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

<em>The actual dimension is 18.28 by 3.28</em>

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