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jekas [21]
3 years ago
6

The factors of 5y^2-2y-7 are (5y-7) and ???

Mathematics
1 answer:
gladu [14]3 years ago
4 0
If we expand bx to jx and kx we have:

5y^2-2y-7

5y^2-7y+5y-7  then factor...

y(5y-7)+1(5y-7)

(y+1)(5y-7)

So the other factor is:

(y+1)
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