3 years ago

The factors of 5y^2-2y-7 are (5y-7) and ???

1 answer:

4 0

If we expand bx to jx and kx we have:

5y^2-2y-7

5y^2-7y+5y-7 then factor...

y(5y-7)+1(5y-7)

(y+1)(5y-7)

So the other factor is:

(y+1)

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