I would answer this question if I had a picture or something to guide me
Answer: A-(2,6)! :)
Explanation:
y < x^2 + 6
6 < 2^2 + 6
6 < 4 + 6
6 < 10 IT WORKS
y > x^2 - 4
6 > 2^2 - 4
6 > 4 - 4
6 > 0 IT WORKS
(Could I also get brainliest please?)
Answer:
two real, unequal roots
Step-by-step explanation:
This is a quadratic equation. The quadratic formula can be used to determine how many and what kind of roots may exist:
Find the discriminant, which is defined as b^2 - 4ac, if ax^2 + bx + c = 0. In this case, a = 1, b = -2 and c = -8, so that the discriminant value is
(-2)^2 - 4(1)(-8), or 4 + 32 = 36.
Because the discriminant is real and positive, we know for certain that we have two real, unequal roots
Answer:
x = 22 (see explanation!)
Step-by-step explanation:
Just with any algebraic equation, you will want to isolate the variable (x). Here's a step-by-step to show you how it's done:
1/7(x + 6) = 4
Multiply by 7 to get rid of the 1/7 (since 7 * 1/7 = 7/7 = 1)
7*1/7(x+6) = 7*4
x+6 = 28
Now, subtract 6 from both sides to isolate x:
x + 6 - 6 = 28 - 6
Finally:
x = 22
(x,y) = (r,16)
With this knowledge, plug in r for x, and 16 for y
16 = 2(r) - 4
Isolate the r, add 4 to both sides
16 (+4) = 2r - 4 (+4)
20 = 2r
Divide 2 from both sides
20/2 = 2r/2
r = 20/2
r = 10
hope this helps
