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vazorg [7]
3 years ago
15

Let f(x) = x2 + 6 and g(x)= x+8/x . Find ( g o f)(­ -7)

Mathematics
1 answer:
poizon [28]3 years ago
7 0
(g o f)(x)=g(f(x))
so

(g o f)(-7)=g(f(-7))=
g((-7)^2+6)=
g(49+6)=
g(55)=
55+8/55=
55 ad 8/55

(g o f)(-7)=55 and 8/55
(if you meant g(x)=(x+8)/x, then the result is 63/55 or 1 and 8/55)
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Answer:

a_n = 2(4) ^{n-1}

Step-by-step explanation:

The sequence shown matches that of a geometric sequence of radius 4. To prove it, divide the term \frac{a_{n + 1}}{a_n} and check that \frac{a_{n + 1}}{a_n}=4

Then the formula that represents this sequence is:

a_n = a_1(r)^{n-1}

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Then the equation is:

a_n = 2(4) ^{n-1}

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Natasha_Volkova [10]

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liq [111]

Answer:

x=-0.6,x=1.52,x=2.08

Step-by-step explanation:

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The graph of the two equations are shown in the attachment.

The points where the two graphs intersected are: (-0.6,0.7),(1.52,-1.42),(2.08,-1.98)

The x-coordinates of the intersection points are the solutions to x^3-3x^2+2=0.1-x.

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gulaghasi [49]

Answer:

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