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Novay_Z [31]
3 years ago
12

Can someone solve this? Im lost .......

Mathematics
1 answer:
Westkost [7]3 years ago
5 0
A.; 14 doesn’t work and neither does 8 or 3.
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If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

y(t) = C_1e^{5t}+C_2e^{6t}

8 0
3 years ago
Dennis has 9.5 weeks to prepare for a bike tour If he rides 8.2 miles each week how many miles will he ride before the bike tour
emmasim [6.3K]
If you have to show your work...

8.2 x 9.5 

    8.2
 x 9.5
-----------
     410
+ 7380
-----------
   7,790 miles

hoped this helped.
6 0
3 years ago
Studies show that a typical giant hummingbird can flap its wings once in 0.08 of a second.
Licemer1 [7]

Answer:

a. 90

b. 360

Step-by-step explanation:

The time taken by humming bird to flap its wings= 0.08 sec

by flying 7.2 seconds a typical giant hummingbird flap its wings \frac{7.2}{0.08} times

= 90 times

Since, A ruby-throated hummingbird can flap its wings 4 times faster than a giant hummingbird, it will flap its wings in every 0.02 sec

so in 7.2 seconds it will flap \frac{7.2}{0.02} times = 360 times

4 0
3 years ago
How do you do 1/8 the sum of 23 and 17
Mariulka [41]
\sf 23+17=40 \\ \\  \frac{1}{8}*40= \frac{40}{8}=\boxed{\sf 5}
6 0
3 years ago
Read 2 more answers
Chang drove 420 miles using 18 gallons of gas. At this rate, how many gallons of gas would he need to drive 357 miles?
qwelly [4]

Answer:

<h2>15.3 gallons</h2><h2 />

Step-by-step explanation:

ratio and proportion

<u>420 miles </u>   =   <u> 357 miles</u>

18 gallons          x gallons

420 (x) = 357 (18)

x = 6426 / 420

x = 15.3 gallons

4 0
3 years ago
Read 2 more answers
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