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3 years ago

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Mathematics

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aniked [119]3 years ago

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Answer:

i really dunonjust need tho points sorry but have a blessed Dayyy

Step-by-step explanation:

You might be interested in

Which ordered pair is in the solution set of the system of linear inequalities? y >3/2 x – 1 y <3/2 x – 1 (–5, 2) (2, 2) (

Vikentia [17]

Answer:

No solution

Option 4 is correct

Step-by-step explanation:

Given: The system of inequality

$y>\dfrac{3}{2}x-1$

$y$

We need to choose correct option.

Option 1: (-5,2)

Put x=-5 and y=2

Equation 1 Equation 2

$2>\dfrac{3}{2}(-5)-1$ $2$

$2>-8.5$ $2$

TRUE FALSE

Option 2: (2,2)

Put x=2 and y=2

Equation 1 Equation 2

$2>\dfrac{3}{2}(2)-1$ $2$

$2>2$ $2$

FALSE FALSE

Option 3: (5,2)

Put x=-5 and y=2

Equation 1 Equation 2

$2>\dfrac{3}{2}(5)-1$ $2$

$2>6.5$ $2$

FALSE TRUE

Option 1, 2 and 3 are incorrect because both equation must be true for solution.

Hence, Option 4 is correct no solution.

6 0

3 years ago

Read 2 more answers

In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%

lions [1.4K]

Answer:

$n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59$

And rounded up we have that n=350

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\aht p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: