How does an online school student go to traditional charter school during c0vid?

Write an exponential function in the form y=ab^xy=ab

ivanzaharov [21]

Answer:

Step-by-step explanation:

let y=ab^x

x=0,y=18

18=ab^0=a

a=18

y=18b^x

when x=2,y=1152

$1152=18b^{2}\\b^{2}=\frac{1152}{18}=64=8^2\\b=8\\so~y=18(8)^x$

7 0

3 years ago

Katrina is asked to simplify the expression .

Lorico [155]

The property of distribution

8 0

4 years ago

Read 2 more answers

Find the prime factorization of 15

Anton [14]

The prime factorization of 15 is 1 * 3 * 5

8 0

3 years ago

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PLEASE AWNSER WILL MARK BRAINLIEST

Ghella [55]

Answer:

quadratic function
y-intercept: y = -6
x-intercepts: x = 2 and x = 6
y = 2, x = 4
y ≥ 0

Step-by-step explanation:

The given graph is a parabola and so it a quadratic function.

The y-intercept is the point at which the curve crosses the y-axis.

From inspection of the graph, this is when y = -6.

The x-intercepts are the points at which the curve crosses the x-axis.

From inspection of the graph, the x-intercepts are x = 2 and x = 6.

The vertex is the turning point of the graph, so the minimum point of a parabola that opens upwards, and the maximum point of a parabola that opens downwards.

From inspection of the graph, the vertex is at (4, 2), so the greatest value of y is y = 2, and it occurs when x = 4.

The curve is above the x-axis between the interval x = 2 and x = 6.

Therefore, the function value is equal to zero or positive in this interval.

So the function value in the given interval is y ≥ 0.

3 0

2 years ago

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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts

kirill115 [55]

Answer:

$z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666$

$p_v =2*P(Z$

If we compare the p value and the significance level given $\alpha=0.02$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=4.5$ represent the sample mean

$\sigma=1.1$ represent the population standard deviation

$n=860$ sample size

$\mu_o =4.6$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal or not to 4.6, the system of hypothesis would be:

Null hypothesis: $\mu = 4.6$

Alternative hypothesis: $\mu \neq 4.6$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(Z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.02$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.

5 0

3 years ago