Let A be college A and let B be College B
A= 14,100
Rule: 1 Year = +1,000 students
B= 34,350
Rule: -1250 per year
1st Answer: 2017
Notice: I didn't show the formula because I'm not %100 sure I'm kind of off so if this is incorrect I'm deeply sorry. I truly am. On the bright side, I think its correct.
Answer:
∠ABC= 45°
Step-by-step explanation:
∠ABC= ∠BCD (alt. ∠s, AB//CD)
(2x +15)°= (3x)°
2x +15= 3x
3x-2x= 15 <em>(</em><em>-2x </em><em>on </em><em>both </em><em>sides)</em>
x= 15
Substituting the value of x:
∠ABC
= ∠BCD
= [3(15)]°
= 45°
12,000,000+400,000+30,000+
You should get it now from my previous answer.
But to apply it.
9 - 8b + 6b
9 + (-8b + 6b) <- Collect like bases (b)
9 + (-2b)
9 - 2b
Therefore it simplified is 9 - 2b
So from what I understand, you would multiply 10m by 5m for the width to get 50m squared, and multiply the 50 by 2 to get 100m for both sides of the width for the pool. Next the length. Multiply 25m by 2.5m to get 62.5m squared. Once again, mutiply it by 2 for both side lengths of the pool to get 125m. Last, add 125m and 100m to get 225m for the concrete border of the pool.