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Lina20 [59]
3 years ago
11

The length of a rectangle is 5 less than twice its width. Find the perimeter of this rectangle if its area is 273 yd2

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0
Let the width be w.

Therefore we know that the length 2w - 5.

We know that area is A = w*l.

Therefore:

273 = w * (2w-5)

Now we can solve for the width.

273 = 2w^2 - 5w

2W^2 - 5w - 273 = 0
We can use the quadratic formula from here where a = 2, b = -5 and c = 273.
w =  \frac{-b \pm  \sqrt{b^2 -4ac} }{2a}

w = \frac{-(-5) \pm \sqrt{-5^2 -4(2)(-273} }{2(2)}
Solving this gives us the possible answers of 13 and - \frac{21}{2}. Since our width can't be negative, we know the answer is 13.
Next, we can plug 13 into the formula for area to find the length.
273 = 13*l
21 = l
We now know the width and length. Finally, the last thing to do is calculate the perimeter using the formula 2w + l2 = P

2(13) + 2(21) = P
26 + 42 = P
68 = P
So, the perimeter of the rectangle is 68 yards.
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The greatest whole possible whole number length of the unknown side is 9 inches.

<h3>How to identify if a triangle is acute?</h3>

Let us have:

H = biggest side of the triangle

And let we get  A and B as rest of the two sides.

Then we get:

If

A^2 + B^2 < C^2

then the triangle is acute

Two sides of an acute triangle measure as 5 inches and 8 inches

The length of the longest side is unknown.

We have to find the length of the unknown side

WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

A^2 + B^2 < C^2

Here in this sum,

a = 5 inches

b = 8 inches

c = ?

Substituting we get,

A^2 + B^2 < C^2\\\\5^2 + 8^2 < C^2\\\\25 + 64= C^2

c < 9

Hence, The greatest whole possible whole number length of the unknown side is 9 inches.

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brainly.com/question/14489478

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2 years ago
Solve the following systems of 3-variable linear equations.​
Dima020 [189]

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Step-by-step explanation:

3 0
3 years ago
Need help ASAP. i forgot all the steps after the Area is solved with 5. or if 25pi is the right answer.
maxonik [38]

Answer:

42.5\:\mathrm{m^2}

Step-by-step explanation:

The area of a sector with measure \theta in degrees is given by r^2\pi\cdot\frac{\theta}{360}, where r is the radius of the sector.

What we're given:

  • r of 5
  • \theta of 195^{\circ}

Solving, we get:

A_{sector}=5^2\pi\cdot \frac{195}{360}=13.5416666667\pi=42.5424005174\approx \boxed{42.5\:\mathrm{m^2}}

*Notes:

  • units should be in square meters (area)
  • the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants
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Is the formula x+1=3/4y linear?
pentagon [3]
Yes, it is.
Formula X+1=3/4y is linear.
7 0
3 years ago
PLZ HELP
charle [14.2K]

Answer:

17 pants and 9 shirts

let x rep pants

let y rep shirts

x + y =26

225 x + 125 y =4950

x = 26 - y

225(26 - y) + 125y= 4950

5850-225y+125y = 4950

5850-100y=4950

-100y=4950-5850

-100y=-900

y=9

x = 26 - (9)

x = 17

3 0
3 years ago
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