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3 years ago

5 pts Evaluate the following expression, let a = -1, b = 3, and c = 0 10c - lla+4

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

3 0

Answer:

the equation is 10c-11a+4 so the ans would be 15.

Step-by-step explanation:

10×0-11×-1+4

0+11+4

15.

I think this is the ans.

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The circumference of a circle is 113.04 centimetres. What is the circle's radius?

Drupady [299]

Answer:

18 centimeters

Step-by-step explanation:

Divide the circumference by π, or 3.14 for an estimation. The result is the circle's diameter.

Divide the diameter by 2.

There you go, you found the circle's radius

6 0

2 years ago

Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70

kumpel [21]

Answer:

His acceleration is $\frac{1}{15}$ meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is $a=\frac{v_{f}-v_{i}}{t}$ , where

$v_{f}$ is the final speed
$v_{i}$ is the initial speed
The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

106 meters/minute (final speed) in 9 seconds

∴ His initial speed $v_{i}$ = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ $\frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}$ meters/second

∴ $v_{i}$ = $\frac{7}{6}$ meters/second

∵ His final speed $v_{f}$ = 106 meters/minute

- Change it the meter per second

∴ $\frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}$ meters/second

∴ $v_{f}$ = $\frac{53}{30}$ meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is $a=\frac{v_{f}-v_{i}}{t}$

- Substitute the values of t, $v_{i}$ and $v_{f}$ in the formula above

∴ $a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}$

∴ His acceleration is $\frac{1}{15}$ meters per seconds²

3 0

3 years ago

Kevin and Randy Muise have a jar containing 92 coins, all of which are either quarters or nickels. The total value of the coins

Artemon [7]

<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or

(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>

7 0

3 years ago

Help answer this plz

Sphinxa [80]

X=-1 is the answer. Hope that helps!

8 0

4 years ago

Read 2 more answers

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .

$A\prime(t) = \dfrac{A}{t}=11.19\cdot1.009^t\ln1.009$

In the year 2014, $t=14$ .

$A\prime(14) =11.19\cdot1.009^14\ln1.009=0.114$

6 0

3 years ago