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Inessa [10]
3 years ago
14

HELPPPPPPPPPPPPPPPPPP

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
5 0
The product of Diego's age and 9 is 162. 'product' is multiplication, 'is' means equal to. So we can write:

\sf d\times 9=162

or

\sf 9d=162
Nookie1986 [14]3 years ago
3 0
162 - 9 = 153. 
d = 153.
Diego is old.
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What is the solution to the inequality –2.1x + 2.9 > 15.5?
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Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

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P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

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P(X > 10) = e^{-0.0435*10} = 0.6473

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P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
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