Ask question

Ask question

All categories

2 years ago

11

On a math test, you obtained a score of 66 points. This was 88% ofthe total number of points on the test. How many total points

were on the test?

1 answer:

Lyrx [107]2 years ago

3 0

Answer:

75

Step-by-step explanation:

Let x be the total points

66/x = 0.88 (88%)

x = 75

You might be interested in

Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi

Viktor [21]

Answer:

The expected cost is $8.75

<em></em>

Step-by-step explanation:

Given

$Time = \{1pm, 2pm, 3pm, 4pm\}$

$C_1 = \$5$ --- If Bob and Anna meet

$C_2 = \$10$ --- If Bob and Anna do not meet

Required

The expected cost of Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

$(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)$ $,(3,4),(4,1),(4,2),(4,3),(4,4)\}$

$n(Bob, Anna) = 16$

The outcome of them meeting at the same time is:

$Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}$

$n(Same\ Time) = 4$

The probability of them meeting at the same time is:

$Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}$

$Pr(Same\ Time) = \frac{4}{16}$

$Pr(Same\ Time) = \frac{1}{4}$

The outcome of them not meeting:

$Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)$

$,(3,4),(4,1),(4,2),(4,3)\}$

$n(Different) = 12$

The probability of them meeting at the same time is:

$Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}$

$Pr(Different) = \frac{12}{16}$

$Pr(Different) = \frac{3}{4}$

The expected cost is then calculated as:

$Expected = C_1 * P(Same) + C_2 * P(Different)$

$Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}$

$Expected = \frac{\$5}{4} + \frac{\$30}{4}$

Take LCM

$Expected = \frac{\$5+\$30}{4}$

$Expected = \frac{\$35}{4}$

$Expected = \$8.75$

<em>The expected cost is $8.75</em>

4 0

2 years ago

Is TAG BAG? IF so, identif th similarity postulate or theorem that applies

kodGreya [7K]

Step 1

Given;

$Triangle\text{ TAG \textasciitilde Triangle BAG}$

Required; To find the similarity postulate or theorem that applies.

Step 2

Both triangles share one side AG

They also have a common angle;

$90^o$

Side AG = 10 units and ∠AGT ≅ ∠AGB.

Thus, options A and B are discarded.

Step 3

Now, as for the SAS criteria, we need two sides to be congruent and their included angles to be congruent.

But, as no other information is given, we cannot determine whether the given triangles are congruent or not.

Therefore, the answer is; Option D

$cannot\text{ be determined}$

4 0

9 months ago

A photograph has a length that is 2 inches longer than its width, x. So its area is given by the expression x(x + 2) square inch

Tatiana [17]

Width = 6 inches I hope this helps!

5 0

2 years ago

please give me the explanation for this question, been on it for like 3 hours and can't get the answer

g100num [7]

Answer: your answer is correct I don't understand why you can't get it

I got the exact same answer

4 0

2 years ago

Read 2 more answers

C. Solve for the missing measurements. <br>m<AZL<br> m AL<br><br>

Margaret [11]

AZL is the correct answer

5 0

2 years ago