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Maslowich
3 years ago
11

On a math test, you obtained a score of 66 points. This was 88% ofthe total number of points on the test. How many total points

were on the test?
Mathematics
1 answer:
Lyrx [107]3 years ago
3 0

Answer:

75

Step-by-step explanation:

Let x be the total points

66/x  = 0.88 (88%)

x = 75

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A triangle has an area of 221.16 in.² the height of the triangle is 29.1 inches what is the length of the base of the triangle
Zigmanuir [339]
The formula you should use is Area = 1/2bh, in other words, area equals half times base times height. Now, substitute everything in, the equation should now be 221.16 = 1/2*b*29.1. This simplifies into 221.16 = 14.55b, now divide 14.55 on both sides, which leaves us to 15.2 = b. However, don't forget the units, which the answer (length of base) should be 15.2 in.^2.
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3 years ago
2. Solve the equation.<br> (50 Points)<br> * =<br> + 9 = 30<br> Enter your math answer
barxatty [35]

Answer:

x= 42

Step-by-step explanation:

x/2+9=30

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3 years ago
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5/7x + 15 - 9/14x - 9
muminat

Answer:

1/14x+6

Step-by-step explanation:

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8 0
2 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
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