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3 years ago

Graph the line using two points.y=- 3/ 5x+2

1 answer:

6 0

Ok for this you just plug any number for x and 2 is your y intercept ... -3/5 is slope slope is the change in y over the change in x so you go down 3 because the 3 is negative and to the right 5 because 5 is positive. so two points on the line y=3/5+2 are (-5,-1) and (-10, -4).

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the sum of 3 decimal numbers is 6. Exactly one of the numbers is less than 1 what could those numbers be.

kati45 [8]

There are infinitely many solutions to this problem (which is why it asks what could those numbers be), so you just have to make one up!

Start with the first sentence.
x + y + z = 6.0

Now one of those numbers has to be less than 1. I'll choose x. And I'll choose a random number, say, 0.7.

0.7 + y + z = 6.0

Now I'll subtract 0.7 from both sides to see what y and z have to add up to.

0.7 + y + z - 0.7 = 6.0 - 0.7
y + z = 5.3

Now I'll choose a random number for y that's less than 5.3.

2.6 + z = 5.3

And subtract 2.6 from both sides to find z.

2.6 + z - 2.6 = 5.3 - 2.6
z = 2.7

And now we have our numbers!
x = 0.7
y = 2.6
z = 2.7

3 0

3 years ago

Which line is most likely to have a slope of 10 ?

hodyreva [135]

The line that is most likely to have a slope of 10 is the second one down

6 0

3 years ago

Read 2 more answers

Al has twice as many cards as Bob, and Jane has three times as many cards as Bob. Together, they have 372 cards. How many cards

Musya8 [376]

Answer: Bob has 62 cards.

All has 124 cards.

Jane has 186 cards

Step-by-step explanation:

Let x represent the number of cards that Bob has.

Al has twice as many cards as Bob. It means that the number of cards that All has is 2x.

Jane has three times as many cards as Bob. It means that the number of cards that Jane has is 3x.

Together, they have 372 cards. It means that

x + 2x + 3x = 372

6x = 372

x = 372/6

x = 62

The number of cards that Al has is

2 × 62 = 124

The number of cards that Jane has is

3 × 62 = 186

8 0

3 years ago

HELP PLEASE 21 POINTS PLEASE HELP ME!!!! <3

Anna007 [38]

n 1 2 3 4 5 6

f(n) 1033 932 831 730 629 528

First term (a₁): 1033 Common difference (d): -101

Explicit rule: $a_{n} = 1134 - 101n$ Recursive rule: $a_{n} = a_{n-1} - 101$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = 1033 - 101(n - 1)$

$a_{n} = 1033 - 101n + 101$

$a_{n} = 1134 - 101n$

***********************************************************************************

n 1 2 3 4 5 6

f(n) -39 -29 -19 -9 9 19

First term (a₁): -39 Common difference (d): +10

Explicit rule: $a_{n} = -49 + 10n$ Recursive rule: $a_{n} = a_{n-1} + 10$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = -39 + 10(n - 1)$

$a_{n} = -39 + 10n - 10$

$a_{n} = -49 + 10n$

***********************************************************************************

n 1 2 3 4 5 6

f(n) 3.75 2.5 1.25 0 -1.25 -2.5

First term (a₁): 3.75 Common difference (d): -1.25

Explicit rule: $a_{n} = 5 - 1.25n$ Recursive rule: $a_{n} = a_{n-1} - 1.25$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = 3.75 - 1.25(n - 1)$

$a_{n} = 3.75 - 1.25n + 1.25$

$a_{n} = 5 - 1.25n$

6 0

3 years ago

Find the 50th term of 0,3,6,9

nalin [4]

$\text{a}_1=0 \ \text{and} \ \text{a}_2=3\\\\\text{r}=\text{a}_2-\text{a}_1=3-0=3\\\\\text{a}_{50}=\text{a}_1+49\text{r}=0+49\cdot3=0+147=147\\\\\huge\boxed{\text{a}_{50}=147}$

7 0

3 years ago