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Alona [7]
3 years ago
5

The seventh grade class is building target areas for a or activity. The based for the game will be a circular shape. The diamete

r of each circle is 5 feet. Approximately how !any square feet of the turf need to be painted for the base circle?
Mathematics
1 answer:
Sedbober [7]3 years ago
6 0

Answer:

78.5

Step-by-step explanation:

pls give me brainliest

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Find the value of x , if log₂ [log₅ (log₃x)] = 0
Lina20 [59]
\log_2 (\log_5( \log_3x)) = 0\\
D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\
D:x>0\wedge x>1 \wedge\log_3x>1\\
D:x>1 \wedge x>3\\
D:x>3\\
\log_5(\log_3x)=1\\
\log_3x=5\\
x=3^5\\
x=243
3 0
3 years ago
At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. M
m_a_m_a [10]

Answer:

0.7 is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory

Step-by-step explanation:

The two events are independent of each other.

Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal  probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2

Substituting the given values we get

Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =\frac{174}{174 +116} + \frac{20}{180 +20}

=\frac{174}{174 +116} + \frac{20}{180 +20}

== \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7

5 0
3 years ago
Write the linear equation in slope intercept form 1,3 and -3,-5
oksian1 [2.3K]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes:

(x_ {1}, y_ {1}) :( 1,3)\\(x_ {2}, y_ {2}): (- 3, -5)

We found the slope:

m = \frac{y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Substituting we have:

m = \frac {-5-3} {- 3-1} = \frac {-8} {- 4} = 2

Thus, the equation is of the form:

y = 2x + b

We substitute one of the points and find the cut-off point:

3 = 2 (1) + b\\3 = 2 + b\\3-2 = b\\b = 1

Finally, the equation is:

y = 2x + 1

ANswer:

y = 2x + 1

3 0
4 years ago
25% of what number is 2?<br><br> show your work
kakasveta [241]

Answer:

8

Step-by-step explanation:

2 4 6 8

4 0
3 years ago
Read 2 more answers
Use the discriminant, b2 - 4ac, to determine which equation has complex solutions.
ruslelena [56]

Using the discriminant, the quadratic equation that has complex solutions is given by:

x² + 2x + 5 = 0.

<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>

A quadratic equation is modeled by:

y = ax² + bx + c

The discriminant is:

\Delta = b^2 - 4ac

The solutions are as follows:

  • If \mathbf{\Delta > 0}, it has 2 real solutions.
  • If \mathbf{\Delta = 0}, it has 1 real solutions.
  • If \mathbf{\Delta < 0}, it has 2 complex solutions.

In this problem, we want a negative discriminant, hence the equation is:

x² + 2x + 5 = 0.

As the coefficients are a = 1, b = 2, c = 5, hence:

\Delta = 2^2 - 4(1)(5) = 4 - 20 = -16

More can be learned about the discriminant of quadratic functions at brainly.com/question/19776811

#SPJ1

3 0
2 years ago
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