Ask question

Ask question

All categories

2 years ago

5

The seventh grade class is building target areas for a or activity. The based for the game will be a circular shape. The diamete

r of each circle is 5 feet. Approximately how !any square feet of the turf need to be painted for the base circle?

1 answer:

Sedbober [7]2 years ago

6 0

Answer:

78.5

Step-by-step explanation:

pls give me brainliest

You might be interested in

A fifth-degree polynomial equation with rational coefficients has the roots 3, 8i, and 7- radical 5. Which are also roots of the

Sliva [168]

Using <u>complex numbers and radicals</u>, it is found that the correct option is C.

When a complex number is a root of a polynomial function, it's conjugate also has to be.

Hence, since 8i is a root of the function, -8i is also a root.

The same is valid for radicals, as they are in the $\pm$ format.

Since $7 - \sqrt{5}$ is a root, $7 + \sqrt{5}$ is also a root.

Hence, option C is correct.

For more on <u>complex numbers and radicals</u>, you can check brainly.com/question/25173944

8 0

2 years ago

What is the height of the trapezoid ? A) 3units B) 5units C) 10units D) 12units

zheka24 [161]

Answer:

b) 5

Step-by-step explanation:

6+10=16

40 times 2 = 80

80 div by 15 = 5

5 0

3 years ago

Read 2 more answers

Abby has a credit card which uses the adjusted balance method to compute finance charges. Her card has an APR of 11.83%, and she

levacccp [35]

The answer to this question is A: 6.08

5 0

3 years ago

Read 2 more answers

(10 - 5x) - (9x) + 9)

Goshia [24]

10-5x-9x+9

19-5x-9x

19-14x

4 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago