0.01 that should be your answer
Answer:
(1 ) Inner curved surface area of the well is 109.9 sq. meters.
(2) The cost of plastering the total curved surface area is 4396.
Step-by-step explanation:
The inner diameter = 3.5 m
Depth of the well = 10 m
Now, Diameter = 2 x Radius
⇒R = D/ 2 = 3.5/2 = 1.75
or, the inner radius of the well = 1.75 m
CURVED SURFACE AREA of cylinder = 2πr h
⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)
= 109 sq. meters
Hence, the inner curved surface area of the well is 109.9 sq. meters.
Now, the cost of plastering the curved area is 40 per sq meters
So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)
= 109.9 x (40)
= 4396
Hence, the cost of plastering the total curved surface area is 4396.
Answer/Step-by-step explanation:
Work your way left to right solving each one going by the rules of PEMDAS
Have a nice day and do a good job, best of luck :)
Answer:
Step-by-step explanation:
According to angle bisector theorem we get the following ratio:
Substitute the lengths and solve for x:
- 77/87.5 = 22/(x - 22)
- 77(x - 22) = 87.5*22
- 77x - 77*22 = 1925
- 77x = 1925 + 1694
- 77x = 3619
- x = 3619/77
- x = 47
