Answer:
The answer is 21 minutes
Step-by-step explanation:
We use the equation Xf = Xo + vt
1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])
2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]
3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]
- Child 1 final position =>
- Child 2 final position =>
4) Sum the equations and equate to 3
5) Substitute the values we already know
6) in 15 + 6 minutes they will be 3miles apart
7) In 21 minutes they will still be able to communicate with one another.
The answer is 2 1/2. Because you need to cross cancel then you take the "freeway", and you get 5/2 and simplified is 2 1/2.And since half equals .5 it would be 2.5 just in case you also needed decimal.
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Answer:
Step-by-step explanation:
Given equation is 
We need to find the value of 
Distribute 
in the right-hand side
Add both sides
Now, add both sides 
Divide both sides by 
So,
The question is find the equation, in the function and standard notations, that represent the amount spent in the range of 0 to 5 rides.
Constant cost: $30
Independent variable, number of rides: r
Variable cost: $2r
Total spend, s(r): 30 + 2r
Function: s(r) = 30 + 2r, for 0 ≤r ≤ 5 ----- this is the function notation
Standard form: s(r) is the dependent variable = s
s = 30 + 2r => s - 2r = 30 =>
s + (-2)r = 30, for 0 ≤ r ≤ 5 ------ this is the standard form
Answer: 57 boys
Step-by-step explanation: Lets break it down right
14th from the top with 10 girls in front which means 3 boys are in front and since there are twice as many girls as boys there are 60 girls and 30 boys so 3 boys are ahead which leaves 57 boys below him
