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2 years ago

Given the following linear function sketch the graph of the function and find the domain and range.

Mathematics

2 answers:

vfiekz [6]2 years ago

6 0

domain of the problem is -5 and the range is 4

katrin [286]2 years ago

3 0

Answer:

$D=x\in R$

$R=x\in R$ .

Step-by-step explanation:

(The graph is attached)

Remember that the domain is the set which contains all the values that x can use. In this case, the x can use all values possible, therefore, we say that the domain is all Real Number Set. $D=x\in R$

Similarly, the range is the set which contains all values that y can use. In this case, the y can use all values possible. Therefore, the range is $R=x\in R$ .

Generally, all linear functions have this domain and range because they don't have any special restriction like rational or irrational functions.

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A pizza had 9/10 left before Lucas ate 4/5 of the pizza. How much pizza is left over

Norma-Jean [14]

1/10 is left.

Explanation:

First we need to find a common denominator. Since 5×2=10, if we multiply 4/5 by 2/2, we will be able to subtract that from 9/10.

4/5×2/2= 8/10. Then if we subtract that from the 9/10 left of the pizza, we get 1/10, the amount remaining.

Hope this helps :)

8 0

2 years ago

Read 2 more answers

F(t)=t^2+19t+60 What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

4 0

2 years ago

On the scale drawing of a car, the length from bumper to bumper is 6 inches. The car’s actual length, from bumper to bumper, is

dimulka [17.4K]

Answer:

3/8 in/ft
1/32 . . . (pure number, no units)

Step-by-step explanation:

The ratio can be expressed directly as ...

... (6 in)/(16 ft) = 3/8 in/ft

This can be read or used in different ways:

3/8 in = 1 ft
3 in = 8 ft

Or, the units can be made compatible and the ratio expressed as a pure number.

... (1/2 ft)/(16 ft) = (1/32) ft/ft = 1/32

This means whatever measurement is made on the model, the actual vehicle measurement is 32 times that.

4 0

3 years ago

Simplify -3x³y²(-4x²y•y•y•y•y)²

AnnZ [28]

$-3x^3y^2(-4x^2 \underbrace{y\cdot y\cdot y\cdot y}_{y^4})^2\\\\=(-3)(-4)(x^3x^2)(y^2y^4)\\\\=12x^{3+2}y^{2+4}\\\\=\boxed{12x^5y^6}\\\\Used:\\\\a^n\cdot a^m=a^{n+m}$

3 0

2 years ago

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Pick any number. If that number is even, divide it by 2. If it's odd, multiply it by 3 and add 1. Now repeat the process with yo

Eva8 [605]

4/2=2+1=3x3=9+1=10/2=5+1=6/2=3+1=4/2

5 0

3 years ago

Read 2 more answers