The amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
<h3>What is compound interest?</h3>
Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-
![A=P[1+\dfrac{r}{n}]^{nt}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7Bn%7D%5D%5E%7Bnt%7D)
a) The amount in the bank after 6 years if interest is compounded annually.
![A=P[1+\dfrac{r}{1}]^{t}\\\\\\A=6000[1+\dfrac{0.01}{1}]^{ 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B1%7D%5D%5E%7Bt%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B1%7D%5D%5E%7B%20%206%7D)
A= $6369
b) The amount in the bank after 6 years if interest is compounded quarterly.
![A=P[1+\dfrac{r}{4}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{4}]^{4\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B4%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B4%7D%5D%5E%7B4%5Ctimes%206%7D)
A= $6090
c ) The amount in the bank after 6 years if interest is compounded monthly.
![A=P[1+\dfrac{r}{12}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{12}]^{12\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B12%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B12%7D%5D%5E%7B12%5Ctimes%206%7D)
A=$6030
Hence the amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
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Answer:
a
Step-by-step explanation:
educational guess ;)
Answer:
The original price was $700.
50% of 700 = 350
Sorry I rlllllyyyyyyy don’t understanddddd
Answer:
C. 11
Step-by-step explanation:
Substituting, we have ...
8{80, 19, 11} ?= 88
{640, 152, 88} ?= 88
The value from the set that makes the equation true is x = 11.
_____
<em>Alternate methods of solution (other than substitution)</em>
It can be easier to make use of your knowledge of factoring:
8x = 8·11
x = 11
Or to make use of your knowledge of numbers (place value):
8·10 = 80
so x will not be very different from 10.