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konstantin123 [22]
3 years ago
14

HELPP !!!! I NEED HELPP Which steps should be used to compare the fractions 2/9 and 5/6?

Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

find a common numerator

Step-by-step explanation:

You might be interested in
The area of a rectangle is 30 square meters. Find the length and width if the length is 1.45 times the width.
lyudmila [28]

Answer:

<u>The length of the rectangle is 14.5√6/29 or 6.6 meters and the width is 10√6/29 or 4.55 meters.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Area of a rectangle = 30 square meters

2. Find the length and width if the length is 1.45 times the width.

Width of the rectangle = x

Length of the rectangle = 1.45x

Now substituting in the formula of the area of a rectangle, this way:

30 = x * 1.45x

30 = 1.45x²

x² = 30/1.45

x = √30/1.45

x = 10 √6/29 or 4.55 (Rounding to two decimal places)

1.45 x = 14.5 √6/29 or 6.6

<u>The length of the rectangle is 14.5√6/29 or 6.6 meters and the width is 10√6/29 or 4.55 meters.</u>

7 0
3 years ago
My number is a 2-digit multiple of 9. The ratio of its units digits to tens digit is 1:2. what is my number? It's not 36 I tried
pentagon [3]

Answer:

63

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
ASAP Plz what is the value of x? Plz no joking around this is from quiz 4.09: Special Right Triangles 2
Sunny_sXe [5.5K]
Ooh this is a good one!
Firstly, let's find RT so that we can solve the top triangle.
We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)

For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
s \sqrt{3}  = 2 \sqrt{3}  \\ s \sqrt{3} \div  \sqrt{3}   = 2 \sqrt{3} \div  \sqrt{3}  \\ s = 2
So now, the hypotenuse (RT) = 2s = 2(2) = 4

Secondly, we are looking at the other type of special right triangle, the 45-45-90:
The side opposite the 45s are s (remember side lengths are equal whose opposite angles are equal); and the hypotenuse is always
s \sqrt{2}
we only need QR, which is s, which is also = RT
So the answer is:
QR = x = 4

x = 4 IS THE FINAL ANSWER!!!


[ i hope by my explanations you understand how better to do special right triangles in the future] :-D
8 0
3 years ago
Read 2 more answers
4x-6 equals -2 algebraically​
Angelina_Jolie [31]

Answer:

x=1

Step-by-step explanation:

4x-6= -2

    +6=+6

   <u>4x</u>=<u>4</u>

    4 = 4

       x= 1

3 0
3 years ago
Find the ratio of the area inside the square but outside the circle to the area of the square in the picture
Eduardwww [97]

Answer:

0.2146

Step-by-step explanation:

From the picture:

The radius of the circle = r. This means that the area of the circle = πr²

Also For the square, the length of the square = 2r, Therefore the area of the square = Length × length = 2r × 2r = 4r²

The area inside the square but outside the circle = Area of square - Area of circle = 4r² - πr² = r²(4 - π) = 0.8584r²

The ratio of the area inside the square but outside the circle to the area of the square =  r²(4 - π) / 4r² = (4 - π) / 4 = 1 - π/4 = 0.2146

5 0
3 years ago
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