how to solve and write three times a number s plus 4 times a number y is 1 more than 6 times the number s. solve for s
1 answer:
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Answer:
F(4) = 9
Step-by-step explanation:
Notice that for f(4), we need to use the function definition for the partitioned Domain that includes x = 4, and that is the expression :
Therefore:
Answer:
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following: