Find the equation of the parabola that has zeros of x = –2 and x = 3 and a y–intercept of (0,

Please help, 50 points, will crown brainliest

VashaNatasha [74]

Answer:Q1 27.6363636 Q2 304/11 = q1 answer

Step-by-step explanation:

8 0

3 years ago

What would be the equation to you have a part time job. You work for 3h on Friday and 6h on Saturday. You also recieve an allowa

HACTEHA [7]

Answer:

Step-by-step explanation:

So, to go about your question, we must first ask, how many hours a week is being worked?

In this problem, that is 9 hours per week.

Next, we must question how much per week is made

That is $92 per week

Finally, we must determine if the allowance is occuring many times in the week or just once.

In this problem, that is only occuring once for the week.

So, the equation we must setup is 9x +20 =92.

To solve the equation, we need to subtract 20 on both sides to isolate the variable, x.

9x+20=92

-20 -20

Now our equation is

9x=72

Now, to finally get x by itself or to isolate x, you should divide 9 on both sides to cancel out the 9 being multiplied by the x.

9 9

x=8 because of 72/9 is equal to 8.

I hope this helps, and I will answer any questions you have.

5 0

2 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago

A jar contains 0.75 liter of blackberry juice and 0.60 liter of blueberry juice. Patrick poured 0.25 liter of guava juice into t

Elza [17]

Answer:

Part A: (0.75 + .25 + .60) - .20 = 1.40

Part B : Addition and subtraction ¯\(°_o)/¯

First parentheses ¯\(°_o)/¯

Then subtract

¯\(°_o)/¯

4 0

3 years ago

The average human body contains about 40 L of water. What is the total amount of water contained in the 6.4 billion people in th

vesna_86 [32]

Answer:

2.56 * 10^11 L

Step-by-step explanation:

1 body has 40 L

Thus, the amount in 6.4 billion would be;

40 * 6.4 * 10^9

= 256 * 10^9

= 2.56 * 10^2 * 10^9

= 2.56 * 10^11 L

7 0

3 years ago

Find the equation of the parabola that has zeros of x = –2 and x = 3 and a y–intercept of (0,–30).