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photoshop1234 [79]
3 years ago
13

I'm studying a new bacteria that doubles in numbers every 25 minutes. If i start with 50 bacteria, how long until i have 5 milli

on of them
Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

415.63 minutes

Step-by-step explanation:

Growth can be represented by the equation A=A_0e^{rt}. We can find the rate at which it grows by using t=25 minutes and \frac{A_{0}}{A} =2 or double the amount at that time. The first step we always take is to divide A_0 by A.

[tex]\frac{A_{0}}{A}=e^{rt}\\2=e^{r(25)}

2=e^{(25)r}

To solve for r, we will take the natural log of both sides and use log rules to isolate r.

ln 2=ln e^{(25)r}\\ln 2=25r (ln e)\\\frac{ln2}{25} =r

We know lne=1 so we were able to cancel it out and divide both sides by 25.

We solve with a calculator \frac{ln2}{25} =r\\0.0277=r

We change 0.0277 into a percent by multiplying by 100 to get 2.77% as the rate.

The equation is A=A_0e^{0.0277t} .

We repeat the step above substituting A=5,000,000, A_0=50, and r=0.02777. Then solve for t.

5000000=50e^{0.0277t}\\\frac{5000000}{50} =e^{0.0277t}\\100000=e^{0.0277t}\\ln100000=lne^{0.0277t}\\ln100000=0.02777t(lne)\\\frac{ln100000}{0.0277} =t

t=415.63 minutes

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