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3 years ago

6

Please help asap! i just need the answers. brainliest to first CORRECT answer!! thanks!

2 answers:

Nata [24]3 years ago

6 0

Answer:

a. 8,953.5 seconds

b. 14,400 seconds

Step-by-step explanation:

kobusy [5.1K]3 years ago

4 0

Answer:

a. 8,953.5 seconds

b. 14,400 seconds (check note)

Step-by-step explanation:

a.

y=-4x

y=-35814 (negative because this is underwater)

-35814=-4x

8953.5

The model suggests it would take 8,953.5 seconds for DeepSea Challenger to reach the bottom (2.487083333 hours, or about 2 hours and 30 minutes).

b.

y=4x

x=3600 (positive because the vessel is rising)

4(3600)

14400

It took 14,400 seconds for the DeepSea Challenger to ascend to the surface.

[also note: I'm not sure if the second question is asking for how many seconds it takes to ascend to the surface with reference to the 4 seconds in the previous question (which is how I answered part b) or if it's asking how many seconds 1 hour is, and in that case. the answer is 3,600 seconds. I hope this helps and sorry if it's unclear!]

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1) Two coins are to be flipped. The first coin will land on heads with probability .6, the second with probability .7. Assume th

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(b) E[X]=1.3

Step-by-step explanation:

(a)

Let A be the event that first coin will land on heads and B be the event that second coin will land on heads.

According to the given information

$P(A)=0.6$

$P(B)=0.7$

$P(A')=1-P(A)=1-0.6=0.4$

$P(B')=1-P(B)=1-0.7=0.3$

P(X=1) is the probability of getting exactly one head.

P(X=1) = P(1st heads and 2nd tails ∪ 1st tails and 2nd heads)

= P(1st heads and 2nd tails) + P(1st tails and 2nd heads)

Since the two events are disjoint, therefore we get

$P(X=1)=P(A)P(B')+P(A')P(B)$

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$P(X=1)=0.18+0.28$

$P(X=1)=0.46$

Therefore the value of P(X=1) is 0.46.

(b)

Thevalue of E[X] is

$E[X]=\sum_{x}xP(X=x)$

$E[X]=0P(X=0)+1P(X=1)+2P(X=2)$

$E[X]=P(X=1)+2P(X=2)$ ..... (1)

First we calculate the value of P(X=2).

P{X = 2} = P(1st heads and 2nd heads)

= P(1st heads)P(2nd heads)

$P(X=2)=P(A)P(B)$

$P(X=2)=(0.6)(0.7)$

$P(X=2)=0.42$

Substitute P(X=1)=0.46 and P(X=2)=0.42 in equation (1).

$E[X]=0.46+2(0.42)$

$E[X]=1.3$

Therefore the value of E[X] is 1.3.

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