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Scrat [10]
3 years ago
6

In Miss Ericksen's class, there are 18 boys and 15 girls. What is the ratio of boys to girls in Miss Ericksen's class? Simplify

your answer.
Mathematics
1 answer:
natka813 [3]3 years ago
3 0

Answer:

6:5

Step-by-step explanation

boys : girls

= 18 : 15

Now time to simplify:

18/3: 15/3

= <u>6:5</u>

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What is the 4th term of the linear sequence below?<br> -9,-5, -1,3,7,...
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Answer:

The 4th term of the linear sequence = 3

Step-by-step explanation:

First term, a = -9

Common difference, d = -5 - (-9)

= -5 + 9

= 4

d = 4

The 4th term of the linear sequence = a + (n - 1)d

where,

n = 4

a + (n - 1)d

= -9 + (4 - 1)4

= -9 + (3)4

= -9 + 12

= 3

The 4th term of the linear sequence = 3

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The answer, is CD. The 3rd one
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A coin sold for ​$264 in 1976 and was sold again in 1989 for $ 459. Assume that the growth in the value V of the​ collector's it
Vaselesa [24]
K=195 is the answer
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3 years ago
If the original quantity is 8 and the new quantity is ​,2 what is the percent​ decrease?
azamat

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Step-by-step explanation:

75% of 8 is 6.

8 was decreased by 6 to get 2.

8 was decreased by 75% of its initial value to get 2.

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3 years ago
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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


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3 years ago
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