X^2 - x - 20
(x + 4)(x - 5) <==
x^2 - x - 20.....the last sign, which is negative, tells me that one set is positive and one set is negative. The first sign, which is also negative, tells me that the larger number will be negative. Now u have to find 2 numbers, that when added equal -1 and when multiplied, equal -20....those numbers are -5 and 4. so ur answer is : (x + 4)(x - 5)
Rewrite using the quotient rule for radicals.<span><span><span>√1/</span><span>√1</span></span><span>44</span></span>Any root of <span>1</span> is <span>1.</span><span><span>1<span>√1</span></span><span>44</span></span>Simplify the denominator.The result can be shown in both exact and decimal forms.Exact Form:1/12Decimal Form:<span>0.08333333333333</span>
<span>5d^2 + 4d - 3 - (3d^2 - 2d + 4)
=</span>5d^2 + 4d - 3 - 3d^2 + 2d - 4
= 2d^2 + 6d - 7
Answer:
<h2>x = 10.3</h2>
Step-by-step explanation:
Use sine.
We have:
<em>look at the table in the picture</em>
Substitute:
<em>multiply both sides by 16</em>
