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igor_vitrenko [27]
2 years ago
7

What the equation in point-slope form, matchs the graphed line shown

Mathematics
1 answer:
Burka [1]2 years ago
7 0
Given points (0, 1) and (-7, 5):

Let (x1, y1) = (0, 1)
(x2, y2) = (-7, 5)

First, solve for the slope of the line using the formula:

m = (y2 - y1)/(x2 - x1)
m = (5 - 1) / (-7 - 0)
m = 4/-7 = -4/7

Now that we have our slope, m = -4/7, we can plug this in, along with one of the given points, (0, 1), into the point-slope form:

y - y1 = m(x - x1)

y - 1 = -4/7(x - 0) ← This is the point-slope form


Please mark my answers as the Brainliest if you find this helpful :)
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Ivahew [28]

Answer:

x^4 + 5x^3 - 12x^2 + 5x + 1

3 0
3 years ago
Read 2 more answers
Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
2 years ago
The volume, V, of a right cone varies jointly with the square of the radius of the base, r, and the height, h. When r = 6 and h
Sveta_85 [38]

Answer:

V=πr^2(h/3)

Step-by-step explanation:

V=π6^2(8/3)

6 0
3 years ago
A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn
tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range


(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)


The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.


The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:


\sigma = \dfrac{ 11}{\sqrt{121}} = 1


So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range


(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)


That's probably the answer they're looking for.



4 0
3 years ago
(2<br> 2X 2<br> −3 ÷ 2<br> 5<br> )<br> 2 =
Pavlova-9 [17]

Answer

Extract form = 2194 /25

Decimal form =87.76

4 0
3 years ago
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