Answer:
The required expression is 
.
The value of the expression when y=20 is 2.
Step-by-step explanation:
Consider the provided phase.
3 less than the quotient of a number y and 4
The quotient of a number y and 4 can be written as: 
Now 3 less than the quotient of a number y and 4 can be written as:
Hence, the required expression is .
Now evaluate when y=20.
Substitute y=20 in above expression.
Hence, the value of the expression when y=20 is 2.
Answer:
Step-by-step explanation:
<h3>Given</h3>
<h3>Find</h3>
- Solve for x
- Find x when p = -5
<h3>Solution</h3>
- 4(px + 1) = 64
- 4(px + 1)/4 = 64/4
- px + 1 = 16
- px = 15
- x = 15/p
<u>When p = -5, substitute p:</u>
Answer:
not really sure can’t see the problem to good but C?
Step-by-step explanation:
hope this helped tho. cross multiple (btw if you search it on google it will help you)
Answer:
x^2+x-4
Step-by-step explanation:
(f-g)=(x^2+1)-(5-x)
=x^2+1-5+x
=x^2+x-4
Answer:
The answer would be B.
Step-by-step explanation:
Hope this helps.
