Answer:
Step-by-step explanation:
f(x)=2(x+4)(x-1)
=(2x+8)(x-1)
<h3>=2x²-2x+8x-8</h3>
=2x²+6x-8
Answer:
(x, y) (1,5.5) , (2,5.75) (3,5.83) (4,5.875) (5,5.9)
Step-by-step explanation:
The x values lie on the horizontal line and the y values lie on the vertical line.
In order to find the value of y you must substitute the value of x in the equation given and you must plot you graph using the answers you got which I wrote for you.
NOTE:if there's anything you don't understand let me know.
So the problem ask to what could be the right choice among the three that could support the said statement in you problem that tells that an angle that has a supplement also has a complement and the best answer would be that it is ALWAYS be TRUE. I hope you are satisfied with my answer
Answer: (-2, 5) and (2, -3)
<u>Step-by-step explanation:</u>
Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:
y - intercept = (0, 1) 2nd point = ( -1, 1).
Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)
<em>see attached</em> - the graphs intersect at two points: (-2, 5) and (2, -3)