Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and having 6 or more girls are :
<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :
- P(X = 6) = 0.111 (from the discrete probability table)
2.)
<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :
- P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8)
- From the table attached :
- P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1
Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1
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-14i is the answer to the equation
Answer:
1079
Step-by-step explanation:
Hello,
18-5 = 13
31-18=13
44-31=13
161=5+13*12
So we need to compute

Thanks
Answer:
66.67%
Step-by-step explanation:
75 /100 = .75
.75n = 45
45/.75 = 60
60 is n
60/90 = .666667
.666667 * 100 = 66.67%
Answer:
6.14125(0.15) = 0.9211875 (below 1)
6.14125 - 0.92118 = 5.22007
Step-by-step explanation:
Given data
1. 10(.15)=1.5
2. 10-1.5=8.5
3. 8.5 (.15)=1.275
4. 8.5-1.275=7.225
continuation the sequence
5) 7.225 (0.15) = 1.08375
6) 7.225 - 1.08375 = 6.14125
7) <u> 6.14125(0.15) = 0.9211875 (below -one)</u>
8 ) <u> 6.14125 - 0.9211875 = 5.2200625 (get number 5)</u>
9) 5.2200625(0.15) = 0.783009
10) 5.2200625 - 0.783009 = 4.4370532