To solve this problem you must apply the proccedure shown below:
1. You have the following equation of a parabola, given in the problem above:
x<span>=1/16y^2
2. Then, based on the graph attached, you have:
p=y^2/4x
p=8^2/(4)(4)
p=64/16
p=4
3. The directrix is:
directrix=h-p
directrix=0-4
directrix=-4
The answer is:-4</span>
X= pi/4 +k(pi)
(This may not be correct sorry)
Answer: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
Step-by-step explanation: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!