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Dmitry_Shevchenko [17]
3 years ago
5

Factor ab + bc + b2 + ac.

Mathematics
2 answers:
Alona [7]3 years ago
5 0
<span>ab + bc + b</span>²<span> + ac = 
(b</span>² + bc<span>)+(ab + ac) = 
b(b+ c)+a(b + с) = 
(b + c)(b + a)</span>
sasho [114]3 years ago
5 0
(ab + b^2) + (bc + ac). 

<span>{So we can get the terms with the same variables together} </span>

<span>Factoring out the GCF from each term: </span>

<span>b(a + b) + c(a + b). </span>

<span>Then, factoring out a + b yields: </span>

<span>(a + b)(b + c). </span>

<span>I hope this helps!</span>
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Answer:

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3 years ago
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Lady_Fox [76]

Answer: The value of n = 7.

Step-by-step explanation:

Since we have given that

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Number of different colored beads = n

With repetitions of colors allowed.

Number of ways = 230,230

So, it becomes

^{20+n-1}C_{n-1}=^{19+n}C_{n-1}=^{19+n}C_{20}

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By hit and trial we get that

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5 0
3 years ago
Please solve and show your work: (-4m^9+2m^7-14m^6)÷2m^3
katrin2010 [14]
The first step for solving this expression is to write the division as a fraction. 
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\frac{2(-2 m^{9} + m^{7}-7 m^{6} )  }{2} × m³
Reduce the fraction with 2.
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Lastly,, distribute m³ through the parenthesis to get your final answer.
-2m^{12} + m^{10} - 7m^{9}
Let me know if you have any further questions.
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4 0
3 years ago
What is 12/35 simplified
Amiraneli [1.4K]

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Thx!

4 0
4 years ago
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ehidna [41]

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8 0
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