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Alex
3 years ago
5

How do you get the answer for .0003 is 1/10 of?

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
0.0003 would be 1/10 of 0.00003. If you divided 0.00003 by 10 you would get 0.0003. In fraction form it is 3/10,000

Hoped this helped. 
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4x−1=3y+5 as a ordered pair
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Answer:

y = 4/3x - 2

Step-by-step explanation:

4x −1 = 3y + 5

    + 1        + 1

4x = 3y + 6

-3y   -3y

-3y + 4x = 6

      - 4x   -4x

-3y = -4x + 6

/-3     /-3

y = 4/3x - 2

*View attached graph for ordered pairs*

Hope this helps!

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3 years ago
Find the point of intersection of the two lines y=3x+2 and y=2x-1
inessss [21]
(-3,-7) because the two lines have different slopes an the point that they intersect is the point i listed above
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What is the slope of the line that contains points (2,3) and (2,-4)
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If a < 0 and c > b, circle the expression that is greater:
matrenka [14]

Answer:

The expression that is greater is a (b - c)

Step-by-step explanation:

  • a < 0 and c > b, this means <u>(by the addition property)</u> that c - c > b - c⇒0 > b - c

so for the product <u>a(b - c) </u>we would have a multiplication of a negative number <em>a</em> and another negative number <em>(b - c)</em>. We know that the result of the <u>multiplication of two negative numbers  is a positive number.</u>

Therefore, a (b - c) > 0

  • a < 0 and c > b, this means <u>by the addition property</u> that c - b > b - b⇒ c - b > 0

so for <u>a(c - b)</u>, we have the negative number <em>a</em> multiplied by the positive number <em>(c - b). </em>We know that the result of the <u>multiplication of a negative number by a positive number is negative. </u>

<u>Therefore  a (c - b) < 0</u>

Thus, the expression that is greater is the positive one which is a (b - c)

5 0
3 years ago
F(x) = 2/x, g(x) = |x| -1 <br><br><br> What is the domain of (fog) (x)?<br><br> will mark brainliest
brilliants [131]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

3 0
3 years ago
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