Answer:
yes
Step-by-step explanation:
if both y and x are 0 than it is true that they equal each other since 0=0
F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
3x² + 8x - 3 = (3x - 1) (x + 3)
Answer:
5/6
Step-by-step explanation:
total possible = 36
Favorable = 6
1 6
6 1
2 4
4 2
3 4
4 3
Part/whole
6/36
= 1/6
NOT = 5/6
Answer:
Step-by-step explanation:
x²-16x+60
=x²-6x-10x+60
=x(x-6)-10(x-6)
=(x-6)(x-10)
so dimensions are x-6 and x-10.