Answer:
im not sure if this is correct but, i got C
Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
Answer:
The midpoint of the segment is (-0.5,0.5).
Step-by-step explanation:
Midpoint of a segment:
The midpoint of a segment is given by the mean of its coordinates.
Segment with end points (4,2),(-5,-1)
x-coordinates: 4 and -5
y-coordinates: 2 and -1
x-coordinate of the midpoint:

y-coordinate of the midpoint:

The midpoint of the segment is (-0.5,0.5).
140 1/8 can not be expressed in radical form because it neither has an exponent or a square root. Unless if 140 is raised to the power of 1/8, then that can be.
Answer: The answer is (C) Exponential.
Step-by-step explanation: We are to select out of the given options the type of graph that a savings account with compounded interest be modelled.
We know that compounding gives more interest because we are earning interest on interest, and not just on the principal.
The formula foe compound interest is given by
where, 'P' is the principal, r is the rate of interest and 'n' is the number of years.
Therefore, we can see that the function is of exponential type.
If we draw the graph of compound interest earned every year with a particular rate of interest is of exponential type.
So, the correct option is (C) Exponential.