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RUDIKE [14]
3 years ago
6

PLEASE HELP!

Mathematics
1 answer:
AnnZ [28]3 years ago
3 0

Answer:

A.30x3-3x2-24x+9

Step-by-step explanation

1. Separate the terms in g(x). (6x) (-3)

2. Distribute by multiplying each term in f(x) by (6x).

   (6x)(5x2+2x-3)=30x3+12x2-18x

3. Distribute the other term in g(x) to each term in f(x).

   (-3)(5x2+2x-3)= -15x2-6x+9

4. Combine the like terms of both answers.

   30x3+12x2-18x-15x2-6x+9= <em><u>30x3-3x2-24x+9</u></em>

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Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

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Sample 2: Intermediate soil

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Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

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Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

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