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3 years ago

PLEASE HELP!

Mathematics

1 answer:

AnnZ [28]3 years ago

3 0

Answer:

A.30x3-3x2-24x+9

Step-by-step explanation

1. Separate the terms in g(x). (6x) (-3)

2. Distribute by multiplying each term in f(x) by (6x).

(6x)(5x2+2x-3)=30x3+12x2-18x

3. Distribute the other term in g(x) to each term in f(x).

(-3)(5x2+2x-3)= -15x2-6x+9

4. Combine the like terms of both answers.

30x3+12x2-18x-15x2-6x+9= 30x3-3x2-24x+9

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Write the equation of the line parallel to the y axis at a distance of 7 units form it to is left

Finger [1]

Answer:

x = -7

Step-by-step explanation:

Two parallel lines are lines that never intersect each other.

The y-axis can be written as x = 0.

Then if we want a parallel line to this one, it must be something like x = b

such that b ≠ 0.

Now we want that the distance between our line and the line x = 0 is 7 units to the left

(remember that the left is the negatie side of the axis)

then we can write:

b - 0 = -7

b = -7

The parallel line is x = -7

6 0

3 years ago

Expand and simplify (x-3)(x-6)

olga2289 [7]

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3 0

3 years ago

A number decreased by 5 is less than 33.

kozerog [31]

Step-by-step explanation:

ket the number be x

Decreased by 5 means x-5

Less than 33 means x - 5 < 33

x < 33 + 5

x < 38

5 0

2 years ago

This is a lot of work into this!

masha68 [24]

The maximum revenue of the craftsman is an illustration of objective function

The craftsman can at most make $500, if he makes 100 bracelets

<h3>How to determine the maximum revenue?</h3>

Represent bracelet with b and necklace with n.

From the question, we have:

b n Total

Unit 10 20 1000

Time 10 40 1600

Cost 5 7.5

So, we have the objective function to be:

Max C = 5b + 7.5n

And the constraints are:

10b + 20n ≤ 1000

10b + 40n ≤ 1600

b ≥ 0

n ≥ 0

From the given graph of the constraints, we have the following feasible points

(b,n) = (0,0) (40,30) (0,50) and (100,0)

Substitute these values in the objective function

C(0,0) = 5(0) + 7.5(0) = 0

C(40,30) = 5(40) + 7.5(30) = 425

C(0,50) = 5(0) + 7.5(50) = 375

C(100,0) = 5(100) + 7.5(0) = 500

The maximum revenue is at the point (100,0)

Hence, the craftsman can at most make $500, if he makes 100 bracelets

Read more about objective functions at:

brainly.com/question/16826001

7 0

2 years ago

Dave sold 60 general and reserved tickets for a concert. He sold general tickets for $10 each and reserved tickets for $15 each

swat32

Answer:

The system is of equations is:

$\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.$

Where g is the amount of general tickets and r is the amount of reserve tickets.

35 general tickets and 25 reserve tickets were sold.

Step-by-step explanation:

Let general tickets be represented by g and reserved tickets be represented by r.

Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:

$10g+15r=725$

And a total of 60 tickets were sold. Hence:

$g+r=60$

Our system of equations is:

$\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.$

We can solve by substitution. First, divide both sides of the first equation by 5:

$2g+3r=145$

Next, we can subtract a variable (r in this case) from the second equation:

$g=60-r$

Substitute:

$2(60-r)+3r=145$

Distribute:

$120-2r+3r=145$

Simplify:

$120+r=145$

Subtract:

$r=25$

Using the previous equation:

$g=60-r$

Substitute and evaluate:

$g=60-(25)=35$

So, 35 general tickets and 25 reserve tickets were sold.

4 0

3 years ago