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DerKrebs [107]
3 years ago
10

A zookeeper has 8 frogs. Each frog eats 3/4 cups of food. How much food does the zookeeper need in total?

Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

can we see the problem please

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Look at the picture and answer question <br> Quick and simple respond pls
gogolik [260]

Answer:

It is not a good model because neither point lies on the line.

Step-by-step explanation:

We can test each point on the equation of the line.

7x - 10y = 3

Point: (8, 5)

7(8) - 10(5) = 56 - 50 = 6

The left side equals 6, not 3, so point (8, 5) is not on that line.

Point: (-12, -9)

7(-12) - 10(-9) = -84 + 90 = 6

The left side equals 6 again, but the right side is 3, not 6.

Answer: It is not a good model because neither point lies on the line.

6 0
2 years ago
What is the value of exppresion if m=3 and n=2 (2m)3 +3(6-n)n?
shtirl [24]

Answer:

102

Step-by-step explanation:

2(3)³ + 3(6-2)2

2 (27) + 3(4)2

54 + 48

102

7 0
3 years ago
Name the property of 5x•(4y+3x)=5x•(3x+4y)
Luba_88 [7]
Associative property of addition
6 0
2 years ago
At a sale, dresses were sold for $90 each. This price was 75% of a
gulaghasi [49]

Answer:

A dress originally costs $120

Step-by-step explanation:

To find the original cost of the dress, we will follow the steps below;

let x represent the original cost of the dress

75% of x  = $90

\frac{75}{100}  ×    x   = $90

\frac{75X}{100}  =   $90

MULTIPLY both-side of the equation by 100

\frac{75X}{100} × 100 =   $90×100

At the right-hand side of the equation, 100 will cancel out 100, leaving us with just 75x

75x = $9000

DIVIDE both-side of the equation by 75

75x/75 = $9000/75

At the left-hand side of the equation 75 will cancel-out 75 leaving us with just x

x=  $9000/75

x = $120

A dress originally costs $120

3 0
3 years ago
How much difference do a couple of weeks make for birth weight? Late-preterm babies are born with 34 to 36 completed weeks of ge
stiks02 [169]

Answer:

a) 0.3277

b) 0.0128

Step-by-step explanation:

We are given the following information in the question:

N(2750, 560).

Mean, μ = 2750

Standard Deviation, σ = 560

We are given that the distribution of distribution of birth weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P (less than 2500 grams)

P(x < 2500)

P( x < 2500) = P( z < \displaystyle\frac{2500 - 2750}{560}) = P(z < -0.4464)

Calculation the value from standard normal z table, we have,  

P(x < 2500) = P(z < -0.4464) = 0.3277 = 32.77\%

b) P ((less than 1500 grams)

P(x < 1500)

P( x < 1500) = P( z < \displaystyle\frac{1500 - 2750}{560}) = P(z < -2.2321)

Calculation the value from standard normal z table, we have,  

P(x < 1500) = P(z < -2.2321) = 0.0128 = 1.28\%

3 0
2 years ago
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