Question

A triangular pyramid had a base with an area of 11.3 square meters, and lateral faces with bases of 5.1 meters and heights of 9 meters. Write an expression that can be used to find the surface area of the triangular pyramid.
Plz explain how you found the answer!!

6th grade go math chapter 11

Thank you bye!!

Answer 1

Answer:

The Surface Area of the pyramid is $103.1m^{2}$

Step-by-step explanation:

The Surface Area Formula for a Triangular Pyramid is the following

$SA = \frac{P*H}{2} +B$

Where:

1. SA is the total Surface Area
2. P is the perimeter of the base
3. H is the slant height of the faces
4. B is the base area.

Since we have all the information already given except for Surface Area we can plug everything into the formula and solve for SA.

$SA = \frac{(4*5.1m) * 9m}{2} + 11.3m^{2}$

$SA = \frac{183.6m^{2} }{2} +11.3m^{2}$

$SA = 91.8m^{2} +11.3m^{2}$

$SA = 103.1m^{2}$

Now we know that the Surface Area of the pyramid is $103.1m^{2}$

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer 2

+Well you need to multiply 11.3 times 4.5 per each triangle
Also you need to find the base which is a square
So 5.1 times 5.1 which is technically 5.1 squared. You add from there

EQUATION: 4(11.3 x 4.5) + 5.1 squared 
You should get 229.41