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3 years ago

Combine like terms 2.4m- 125 + 1.8b+ 92.4

Mathematics

2 answers:

Brut [27]3 years ago

7 0

Answer:

2.4m+1.8b−32.6

Step-by-step explanation:

Group like terms together

1. 2.4 m + \left( - 125 + 92.4 \right) + 1.8 b2.4m+(−125+92.4)+1.8b

2 . Add or subtract the numbers

2.4 m- 32.6 + 1.8 b2.4m−32.6+1.8b

3 . Rearrange the expression

2.4 m + 1.8 b- 32.62.4m+1.8b−32.6

son4ous [18]3 years ago

7 0

Answer:

2.4m+1.8b-32.6

Step-by-step explanation:

2.4m- 125 + 1.8b+ 92.4

2.4m+1.8b-32.6

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gladu [14]

Answer:

x = 4√5

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Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

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Step-by-step explanation:

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3 0

3 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

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3 years ago

HELP PLEASE I WILL MARK YOU BRAINLIEST Jermias buys 6.5 pounds of ground beef at the grocery store. Ground beef costs $5.50 for

Svetlanka [38]

Answer: $35.75

Step-by-step explanation: 6.5x5.5=35.75

4 0

3 years ago

Read 2 more answers

3 1/4 × 4 I really need help for my extra credit homework

FromTheMoon [43]

13 because 1/4 times 4 is 4/4 with makes is a 1
And 3 times 4 is 12
1+12=13.

6 0

3 years ago

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

4 years ago

Combine like terms 2.4m- 125 + 1.8b+ 92.4​

Combine like terms 2.4m- 125 + 1.8b+ 92.4