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saw5 [17]
2 years ago
9

Help me pleeeaaaasssseeee!!!!!!!

Mathematics
2 answers:
telo118 [61]2 years ago
4 0
(3x+1)(3x-13)


You break it apart, then take out a common factor. Hope this helps! 
Gnesinka [82]2 years ago
3 0
Sorry cant help you, that's a tough nut to crack! good luck though!
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For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation c
Illusion [34]

Answer: Our required equation would be 6=\dfrac{c}{2}+1

Step-by-step explanation:

Since we have given that

Amount that Anderson earns per hour = $6

According to question, Anderson earns $1 more than half of Carey's hourly rate.

Let the hourly rate of Carey be 'c'.

So, it becomes,

6=\dfrac{c}{2}+1

And the value of c would be

6=\dfrac{c}{2}+1\\\\6-1=\dfrac{c}{2}\\\\5=\dfrac{c}{2}\\\\c=\$10

Hence, our required equation would be 6=\dfrac{c}{2}+1

5 0
3 years ago
Wench model represents the factors of x^2+9x+8?
LenaWriter [7]
I don't know go to the photo math or others xxx2
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3 years ago
F(x) = 2x2 - 5<br> and<br> g(x) = 5x + 7<br> Find<br> f(g(x)) = [ ? ]x2 + [ ]x +
lbvjy [14]

Answer:10x^2 -18

Step-by-step explanation:since f(x) is becoming the new x then youd subtitute the equation into the x of the g(x) equation. which would be 5(2x^2 -5) +7 which is 10x^2 -25 +7.and you'd simplify from there.

8 0
2 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
2 years ago
Read 2 more answers
Tickets for the basketball game cost 14$ each. If the sale of the tickets brought in 2,212$, how many tickets were sold?
rosijanka [135]
15.78 is the answer to the qustion that you have asked.
5 0
3 years ago
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