Anyone sees the problem? I can’t see it.
Answer:
Step-by-step explanation:
A= πr2 = π·72 ≈153.93804
Center will be (6,-4) and the radius will be square root of 7
AC is a common side, ∠ACD = ∠ACB and CD = BC ⇒ ΔACD and ΔABC <span>are congruent (SAS definition).
</span>Congruent triangles have exactly the same three angles, so ∠D = ∠B.<span>
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