Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Total area of the ends: 2(2")(6") = 24 in^2
Total area of the sides: 2(2")(9") = 36 in^2
Are of the bottom : 1(6")(9") = 54 in^2
Total surface area to be covered = (24+36+54) in^2
X + 12 = n
N is 5 more than twelve so add 5 to 12 and you get 17.
AB=DC because they have the same side lengths
That would be 1/4 * 28 = 7 ins^2
