Question

3x+2y=7,2x-5y=11. By elimination method, need all steps

Answer 1

Answer:

x = 3 and y = -1

Step-by-step explanation:

It is given that,

3x + 2y = 7   ----(1)

2x - 5y = 11    ---(2)

To find the solution of given equations

eq(1) * 2 ⇒

6x + 4y = 14    ----(3)

eq(2) * 3 ⇒

6x - 15y = 33  ----(4)

eq(3) - eq(4) ⇒

6x + 4y = 14    ----(3)

6x - 15y = 33 ----(4)

        19y = 19

y = -1

Substitute the value of y in eq (1) we get,

3x + 2y = 7   ----(1)

3x + (2 *-1) = 7

3x = 7 + 2 = 9

x = 9/3 = 3

Therefore x = 3 and y = -1

Answer 2

Answer:

$x=3,\ \ y=-1$

Step-by-step explanation:

We have the following two equations:

$3x+2y=7$

$2x-5y=11$

To solve the system by the elimination method multiply the first equation by $\frac{5}{2}$ and add it to the second equation

By multiplying the first equation by $\frac{5}{2}$ you get the following:

$\frac{15}{2}x+5y=\frac{35}{2}$

Now we add the two equations

$\frac{15}{2}x+5y=\frac{35}{2}$

$2x-5y=11$

---------------------------------------------------------

$\frac{19}{2}x=\frac{57}{2}\\\\19x=57\\\\x=\frac{57}{19}\\\\x=3$

Now substitute the value of x in either equation and solve for y

$2(3)-5y=11$

$6-5y=11$

$-5y=11-6$

$-5y=5$

$y=-1$