If f(x) = 4x - 12, what is f(2)? O A. -4 O'B. 4 O c. -20 D. 8 Helpppp plzzz

Lanie’s room is in the shape of a parallelogram. The floor of her room is shown and has an area of 108 square feet. Lanie has a

kodGreya [7K]

Answer:

10 yrucv jcyfb vuhc uyc huc hch b

8 0

3 years ago

144 students enter a spelling bee, but only 1/6 of the group will make into the semi-final round, and only 2 /3 that group will

DerKrebs [107]

Answer:

16 students

Step-by-step explanation:

144 students enter a spelling bee contest.

Step 1

For the semi final round we are told that only 1/6 of the group will make it into that round.

This is calculated as

1/6 × 144/students = 24 students.

This means that only 24 students would make it into the semi final rounds.

Step 2

We are also told in the question that only 2/3 of THAT group would make it into the final round.

" THAT" group been referred to in the question means the number students that made it to the semi final round

This is calculated as

2/3 of that group( the group that made it to the semi finals)

= 2/3 × 24 students

= 16 students.

Therefore, the number of students that will enter the final round of the spelling bee is 16 students.

6 0

3 years ago

A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects

Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $p=10$ groups and on each group from $j=1,\dots,p=10$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

Solution to the problem

Part a

(i) confidence interval

False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.

(ii) t-test

Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.

(iii) ANOVA

This one is the best method when we want to compare more than 1 group of means.

(iv) Chi square

False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.

Part b

The ANOVA test is more powerful than the t test when we want to compare group of means.

8 0

4 years ago

A number cube is rolled three times. Find the probability of each sequence of rolls. even, even, odd

Anni [7]

Answer:

I'm assuming that the cube is labelled 1-6. There are 6 * 6 * 6 = 216 total outcomes. There are 3 evens and 3 odds so there are 3 * 3 * 3 = 27 successful outcomes. Probability will be 27 / 216 = 1 / 8.

8 0

3 years ago

Kyle plays softball. His goal is to have a batting average of .400 or greater by the end of the season. The ratio that relates t

gregori [183]

Answer:

The number of hits is $T \ge 30 \ hits$