Question

A = 40, c = 41, b = 1 9 57 81

Answer 1

Answer:

Option C is correct

the value of b approximately is, 57 units

Step-by-step explanation:

Using Pythagoras theorem in a right angle triangle:

$\text{Hypotenuse side}^2=\text{Opposite side}^2+\text{Adjacent side}^2$

As per the statement:

In ACB,

a = 40 units , c = 41

Solve for b:

Using Pythagoras theorem;

$b^2=a^2+c^2$

Substitute the given values we have;

$b^2 = 40^2+41^2$

⇒$b^2 = 3281$

⇒$b = \sqrt{3281} = 57.280014$ units

Therefore, the value of b approximately is, 57 units

Answer 2

$A = 40, c = 41, b = ? \\ \\ \cos{\angle A}= \frac{c}{b} \\ \\ \cos{40^o}= \frac{41}{b} \\ \\b=\frac{41} {cos{40^o}}= 53.5$