The probability of having lunch together is p = 40% = 0.4
The probability of not having lunch together is q = 1 - p = 0.6
Number of trials (days in a week) is n = 7
Let r = number of days in the week when Andy and Anna have lunch together.

Use th graphing calculator to obtain
P(6 of 7) = ₇C₆ (0.4)⁶(0.6) = 0.017
P(7 of 7) = ₇C₇ (0.4)⁷(0.6)⁰ = 0.002
Therefore
P(at least 6 of 7) = P(1 of 7) + P(2 of 7) + ... + P(6 of 7)
= 0.131 + 0.261 + 0.290 + 0.194 + 0.077 + 0.017
= 0.97 or 97%
P(at least 6 of 7) = 0.017 + 0.002 = 0.019 = 1.9%
P(exactly 6 of 7) = 0.017 or 1.7%
Answer:
The probability of having lunch at least 6 days per week is 0.019 or 1.9%.
The probability of having lunch exactly 6 times is 0.017 or 1.7%
Answer:
The answer is negative 24.
Step-by-step explanation:
(−4)(2)+(8)(−3)+12−(8)(2)+(−2)(−3)+6
=−24
I hope this helps you with your question
Area of a circle = π * r²:
π * 6² = 113.09
904.78 / 113.09 = 8.00 (rounded)
The height is 8.00 cm
Hope this helps! :)
The answer would be B because it demonstrates the fact that if a is decreased by the quotient of b and c then the second expression wouldn't result into that same answer due to the different arrangements of the signs.
9514 1404 393
Answer:
571,725 J
Step-by-step explanation:
KE = 1/2mv²
KE = 1/2(1050 kg)(33 m/s)² = 571,725 J