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Brilliant_brown [7]
3 years ago
13

What is the value of v? 45(v−7)=2

Mathematics
2 answers:
luda_lava [24]3 years ago
7 0
<span>45(v−7)=2
45v - 315 = 2
45v = 317
v = 317/45
v = 7 2/45 (7 and 2/45)</span>
Pachacha [2.7K]3 years ago
4 0
It's 9 1/2 I just took the test.
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(-8, 7) would be the answer
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A piece of silver has a mass of 2800 grams and occupies a volume of 266 cm3 What is the density of silver
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3 years ago
A horse had 4 1/5 scoops of oats in his bucket. He ate 2 1/2 scoops of oats.
EastWind [94]

The horse has 4\frac{1}{5} oats = \frac{21}{5} oats

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4 years ago
If prices Increase at a monthly rate of 2.3%, by what percentage do they increase in a year?
AlekseyPX
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3 0
4 years ago
A system has 4 components. We want to find the probability that in some implementation of this system components #1 and #2 fail,
alexira [117]

Answer:

The probability that components #1 and #2 fail,  and at least one of components #3 and #4 fails is 0.031875

Step-by-step explanation:

Let's define the following events,

F1: Component #1 fails

F2: Component #2 fails

F3: Component #3 fails

F4: Component #4 fails

We are looking for the following probability

P[(F1∩F2)∩(F3∪F4)]

using distributive laws we have

P[(F1∩F2)∩(F3∪F4)] = P[(F1∩F2∩F3)∪(F1∩F2∩F4)] = P(F1∩F2∩F3) + P(F1∩F2∩F4) - P(F1∩F2∩F3∩F4) = P(F1)P(F2)P(F3) + P(F1)P(F2)P(F4) - P(F1)P(F2)P(F3)P(F4) = (0.25)(0.25)(0.3) + (0.25)(0.25)(0.3) - (0.25)(0.25)(0.3)(0.3)=0.031875

by the assumption of independence (the components fail independently) and because P(F1) = P(F2) = 0.25, P(F3) = P(F4) = 0.3

3 0
4 years ago
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