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UkoKoshka [18]
3 years ago
5

Find a number that is not a solution to 3x-1>8 or 7-x>3

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

All of the numbers are solutions.

Step-by-step explanation:

<u>Step 1:  Solve for x in the first equation </u>

3x - 1 + 1 > 8 + 1

3x / 3 > 9 / 3

x > 3

<u>Step 2:  Solve for x in the second equation </u>

7 - x - 7 > 3 - 7

-x / -1 > -4 / -1

Since you divided by a negative, you must flip the sign.

x < 4

<u>Step 3:  Find the number </u>

x > 3 and x < 4

Answer: All of the numbers are solutions.

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Help pls iready math equation
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Answer:

4 and 5

Step-by-step explanation:

n + 1 > 4

n > 4 - 1

n > 3

For the set { 1, 2 , 3 , 4, 5 }, 4 and 5 are greater than 3.

Hence, 4 and 5 makes the inequality n + 1 > 4 true.

4 0
2 years ago
Help please with 1 and 2. Brainliest
stealth61 [152]

This is for #1

(9-4)(7+6)=41

(24/6)-(2x8)=48

8 0
3 years ago
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a telephone technician charges $30 per hour plus a $45 service charge your father's firm hires him to hook up his company's phon
hodyreva [135]

y=mx+b

y=30h + 45

h= 6.5h

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3 years ago
3+(4+5) = ( 3+4 ) +5.THIS IS AN EXAMPLE OF THE ---------OF WHOLE
navik [9.2K]

Answer:

D.

Step-by-step explanation:

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8 0
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A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he
Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as R(x)=80x-0.2x^ 2 . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ R(x)=80x-0.2x^ 2

⇒ \frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}

⇒ \frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}

⇒ 0=80-2x(0.2)

⇒ \frac{80}{0.4}=x

⇒ x=200

Now , Value of function at x=200 is :

⇒ R(200)=80(200)-0.2(200)^ 2

⇒ R(200)=16000-8000

⇒ R(200)=8000

Therefore , The maximum units is 200 and , Total revenue is $8,000

7 0
3 years ago
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